Question: 1 / 145

A wooden rectangular object is 15cm high. What is the pressure exerted by the object on the ground if the density of wood is 600 kg/m³ and g = 9.81 m/s²?

88290 Pa

883 Pa

To find the pressure exerted by the wooden object on the ground, we first need to calculate the weight of the object and then use the area over which it applies that weight.

1. **Calculate the volume of the wooden object:**

Since we are not given the base area, we can still express the volume \( V \) in terms of area \( A \) and height \( h \):

\[

V = A \times h

\]

The height \( h \) is given as 15 cm, which we need to convert to meters:

\[

h = 15 \, \text{cm} = 0.15 \, \text{m}

\]

So,

\[

V = A \times 0.15

\]

2. **Calculate the mass of the object using its density:**

The density \( \rho \) of wood is given as 600 kg/m³. The mass \( m \) can be found using the formula:

\[

m = \rho \times V = 600 \, \text{kg/m}^3 \times (A \times 0.15) =

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882 Pa

500 Pa

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